Видео

15:20 so much redundant text 🫠

Thank you man.

Thank you sir!! i really enjoyed the way you teach perfectly explained well done sir keep up the good work ✨❤

The very best 🔥 🔥

Wowooo what a good lecture ❤

Good explanation, continue❤

As I know JPE & JPO is not in 8085, it's in 8080 & Z80. Let me know if I'm wrong

after watching about 10 vidios finally I understood what is actually compensation theory. thank you Sir

this helped me so much. thank you!!

Thank you!

Nice video

❤

What is operand

Nice explanation

great dear sir

You have a good accent for an Indian good job

Found bandwidth(BW) in active band pass filter experiment as about 1kHz ,but it has been designed for 500 Hz. Please clarify Also, tell how to find BW

❤

Man such a great explaination! Thank you!

Great vid. Thankyou so much for this

I have struggled to understand this topic. This has been a tremendous help.

blessing is disguise! i have microprocessor reappear exam in a week! i'm really thankful i found you! really excelllently explained things!!

amazing work sir! really helpful... i just dont understand yt , why its not famous? you've explained everything crystal clear!!

Your explanation is very useful for me. I easily understood.

amazing explanation, thank you for clearing all my doubts

Amazing Explanation sir!

The differentiator shown in the beginning isn't stable. Just sayin.....

Fake accent🤢🤮🤮

Once again I am very happy that you are back.. ❤❤❤Love from kolkata

شكرا جزيلا لك.شرح جميل وواضح .اشكرك.

Finally, a video that actually explains how it works, thank you

Your are helper

In XOR, same value's result gives 0 whereas different value's result gives 1.....The table at 13:04 is of XNOR

The worst description I have ever heard.

very well explained 👌

doesnt sign bit mean positive or negative

hey thanks for ur effort . do u have any notes

Thank you sir very nice gide & very nice best information subroutine instruction teaching video.👍

Awesome man💪💪😇

His name was otto schmitt haha. Rhanks for the video

Thanks a lot bro Good teaching skills 👍 👌

nicely explained

Awesome

Thank you very much for your good explanation

a quick example would be helpful.

Thank you lots

thanks for the help for my presentation

Thank you so much!

How to explain something completely ass-backwards. Plots don't 'obtain' equations: equations lead to plots. The concept of upper and lower cutoff frequencies is redundant in low-pass or high-pass filters: there is just a cutoff frequency. There's not much point in talking about cutoff frequencies before stating what w0 means. Cutoff frequencies and band-passes and band-stops and orders appear in all filters, not just Butterworths. Many filters tend to flat cutoff slopes, not just Butterworths, and the graphs drawn with the little curls near zero do not illustrate that correctly. Butterworth filters are not just flat but _maximally_ flat in the passband, and _this_ is what distinguishes them from all others. The gain of an HPF does not decrease with frequency. f0 does not represent the frequency of the signal. The cutoff frequency is not 'about' but _exactly_ the 1/sqrt(2)) point, by definition. _n=1_ defines a 2nd-order Butterworth filter, not s first-order, and there is no such thing as a first-order Butterworth. Similarly _n=2_ defines a fourth order.The rate of change of gain in a Butterworth filter with _n=1_ is not 'about 20 dB/decade' but _exactly_ 40dB/octave, again by definition, and again there is no such thing as a 20dB/decade Butterworth filter.. Filters are not confined to radio frequencies. The ideal for _any_ filter is A=1 in the passband and A=0 in the stop band: not just for Butterworths.Too much waffle and nonsense here, and several major errors.

Really I must say that like book should not be judged by it's cover, no.of likes is no way a parameter to judge the content. SUPERB Explanation. Literally all it took was these 17 minutes to clear the doubts. Thanks a lot mate. Keep it up. Best wishes 😃😃😃😃